2[z+1]-3=z-2

Solution for 2[z+1]-3=z-2 equation:

Simplifying
2[z + 1] + -3 = z + -2

Reorder the terms:
2[1 + z] + -3 = z + -2
[1 * 2 + z * 2] + -3 = z + -2
[2 + 2z] + -3 = z + -2

Reorder the terms:
2 + -3 + 2z = z + -2

Combine like terms: 2 + -3 = -1
-1 + 2z = z + -2

Reorder the terms:
-1 + 2z = -2 + z

Solving
-1 + 2z = -2 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-1 + 2z + -1z = -2 + z + -1z

Combine like terms: 2z + -1z = 1z
-1 + 1z = -2 + z + -1z

Combine like terms: z + -1z = 0
-1 + 1z = -2 + 0
-1 + 1z = -2

Add '1' to each side of the equation.
-1 + 1 + 1z = -2 + 1

Combine like terms: -1 + 1 = 0
0 + 1z = -2 + 1
1z = -2 + 1

Combine like terms: -2 + 1 = -1
1z = -1

Divide each side by '1'.
z = -1

Simplifying
z = -1